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A 1.2 kg block of ice is initially at a temperature of -5°C. (a) If 5.8 multiplied by 105 J of heat are added to the ice, what is the final temperature of the system? °C (b) Suppose the amount of heat added to the ice block is increased by a factor of 3.0...

A heat transfer of 8.7 multiplied by 105 J is required to convert a block of ice at -12°C to water at 12°C. What was the mass of the block of ice?

Q1= 1.2 x 2.05 x 5 = 12.3 q2= 1.2 x 333 = 399.6 q1 + q2 = 411.9 580000 - 411.9 = 579588.1 what did i do wrong?

no idea