Asked by lyd
A heat transfer of 8.7 multiplied by 105 J is required to convert a block of ice at -12°C to water at 12°C. What was the mass of the block of ice?
Answers
Answered by
Jeremy
If I'm not mistaken, it's 9.097155832 grams, which you can round as you see fit.
913.5 J = m x specific heat water x 24 degrees Celcius.
Specific heat of water is 4.184 J/(gC).
Solve for m.
913.5 J = m x specific heat water x 24 degrees Celcius.
Specific heat of water is 4.184 J/(gC).
Solve for m.
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