johnathon

Who roamed ancient Roman roadsides waiting for unwary travelers during the medievel period?

how many terms of the series 1/(n*(ln(n)^8)) from n=2 to infinity would you have to add to find the sum to within 0.01

How do you find the ariea between these curves? y=4x^2 y=7x^2 4x+y=3 x>=0?

sqrt(16)=4 t=d/4 t=4 4=d/4 d=16 the hammar was dropped from 16 feet

1.9%=(1.9)/100 i am not sure that there is an annual interest formula but it might be compounded interest where interest is compounded once a year. the compound interest formula is A=p(1+r/n)^n*t where p is the principle r is the rate n is the compounding...

x/x-.5=2x/2x-1 I got that by multiplying by 2/2

multiply and divide by 6 6c+60=6((6c+60)/6)=6(c+10)

x=2/9*(g(x)-4/g(x)) root=none yint=4 vertical asyntote x=2/9 limit at x approches infinity=0 I hope this helps. it will be easier to help you if you post the whole problem

Use the quotient rule (gf’-fg’)/g^2 where f is the numerator and g is the denominator. For number 1 f=2x+5 so f’ is 2 and g is 3x-2 so g’ is 3 The derivative is ((3x-2)2-(2x+5)3)/(3x-2)^2 After simplifying the final answer is –19/(3x-2)^2 For number 2 rew...

the limit of ab does not always = the limit of a * limit b use lpatls rule i am probboly spelling that wrong but it says that the limit at x approches a of f/g = the limit as x approches a of f'/g' this is only true if the function is of the indeterminate...

thanks that makes sense

use lptals rule the derivative of tan(5x)=sec(5x)^2 the derivative of sin(25x)=cos(25x)*5 the lim of tan(5x)/(sin(25x))=the lim of sec(5x)^2/(cos(25x)*5) direct substution will work for this limit so I will evaluate at 0 the answer is 1/5

what is delta x approching? if it is approching 0 this is the definition of the derivative. so it will be 8x-3. I got this by using the rule that the derivative of ax^n=n*a*x^n-1. but they probboly want you to do it without taking the derivative.so lets s...

the velocity at time t is the derivative. the derivative of s(t) with respect to t = -A*sin(ùt + ä)(t) assuming that everything but t and s(t) are constent. to find out when the velocity is 0 we just have to set the derivative = to 0 and solve for t so it...

thanks the exact answer is 29/294