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horseman
Answers (2)
I have tried to solve it through the trigonometrics way. If in the iteration m you have probability 0 for the rest of the situations, then cos[(2k+1)g] = 0 becasuse of that k=(pi/(4*g))-(1/2) and you know that cos(g)=sqrt(k-1)/sqrt(k) so you have the value
I think the same, that in first case you don´t have to do anythin, and in the second case it´s a bit flip, but it is not correct, why? I think it´s because the sign basis used at the begining? So which could be the correct answer?