Asked by helpless
Suppose we ran m steps of Grover's algorithm on some function f (which has one marked element y) and the resulting superposition was exactly |y>.
(a) What was the state after the (m−1)th step? Note that you can describe the superposition by specifying two numbers, αy and αx for x≠y. Use K to denote the total number of elements. Please fully simply your answer.
Answer in this format: αy: αx for x≠y:
(b) Now, if we run one more step (total of m+1 steps), what is the resulting superposition?
Answer in this format: αy: αx for x≠y:
(c) What if you now apply another phase inversion?
Answer in this format: αy: αx for x≠y:
(a) What was the state after the (m−1)th step? Note that you can describe the superposition by specifying two numbers, αy and αx for x≠y. Use K to denote the total number of elements. Please fully simply your answer.
Answer in this format: αy: αx for x≠y:
(b) Now, if we run one more step (total of m+1 steps), what is the resulting superposition?
Answer in this format: αy: αx for x≠y:
(c) What if you now apply another phase inversion?
Answer in this format: αy: αx for x≠y:
Answers
Answered by
s
PLS HELP
Answered by
Anonymous
help guys
Answered by
My
Anyone please?
Answered by
Anónimo
So the state is at |y> after m steps. So the probability of getting that is 1 and the rest is 0. So What is the mean and what if we move 1 step forward? Is the the same as moving 1 step back?
Answered by
horseman
I have tried to solve it through the trigonometrics way. If in the iteration m you have probability 0 for the rest of the situations, then cos[(2k+1)g] = 0 becasuse of that k=(pi/(4*g))-(1/2) and you know that cos(g)=sqrt(k-1)/sqrt(k) so you have the value of k and the value of cos(g) so you can apply it to k-1 and try to solve the values of coefficients with the aid of the trigonometrics functions. However the marker gives me a red cross, I don´t know what I´m doing wrong! Please help.
Answered by
Anonymous
Problem 4,5,10,11 answers guys
Answered by
Anonymous
12 a and 13 a also pls guys
Answered by
FLu
Problem 10
1; -1
-1; 1
Problem 11
0000
0000
0010
0001
Anyone for Problem 4 and 5 please?
1; -1
-1; 1
Problem 11
0000
0000
0010
0001
Anyone for Problem 4 and 5 please?
Answered by
Anonymous
Thanks flu
Answered by
FLu
No prob anynomous.
Problem 13 a
1; 0
0; 5
Problem 12 a
-1, 3
Would be nice if someone could figure out 4 and 5.
Problem 13 a
1; 0
0; 5
Problem 12 a
-1, 3
Would be nice if someone could figure out 4 and 5.
Answered by
Maverick
12(a) The answer is −1,3
The states of definite energy and their energy are given by the eigenvectors and eigenvalues of the Hamiltonian. In this case, the eigenvectors are |+> and |−> with eigenvalues 3 and −1 respectively.
The states of definite energy and their energy are given by the eigenvectors and eigenvalues of the Hamiltonian. In this case, the eigenvectors are |+> and |−> with eigenvalues 3 and −1 respectively.
Answered by
Anonymous
Thank you all.
And does anyone can help me with p1,p5 and p13
And does anyone can help me with p1,p5 and p13
Answered by
FLu
Problem 1
a)No
b)1
c)a; -b
Problem 13
a)
1; 0
0; 5
b)Last tick for multiple question
c)0
d)0
Anyone for Problem 5 though please?
a)No
b)1
c)a; -b
Problem 13
a)
1; 0
0; 5
b)Last tick for multiple question
c)0
d)0
Anyone for Problem 5 though please?
Answered by
Mur
Yes, anyone for Problem 5 please!
Answered by
rih
Problem 6 please!
Answered by
Anne
For the problem 6 the solution is "1"
Anyone tried the problem 5?
Anyone tried the problem 5?
Answered by
plz help
please guys problem 5
Answered by
Thank you so much!!
hi guys solution for Problem 4 and 5? PLease
Answered by
rih
problem 4
- 1/sqrt(8) ,1/sqrt(8)
- - 1/sqrt(8) , 1/sqrt(8)
- 5/(2*sqrt(8), 1/(2*sqrt(8)
- -5/(2*sqrt(8)) , 1/(2*sqrt(8))
- 11/(4*sqrt(8)), -1/(4*sqrt(8))
problem 5 ???????
- 1/sqrt(8) ,1/sqrt(8)
- - 1/sqrt(8) , 1/sqrt(8)
- 5/(2*sqrt(8), 1/(2*sqrt(8)
- -5/(2*sqrt(8)) , 1/(2*sqrt(8))
- 11/(4*sqrt(8)), -1/(4*sqrt(8))
problem 5 ???????
Answered by
FLu
Yes guys, Problem 5 please?
Answered by
Gyanno
12b please and 5?
Answered by
FLu
12)b
fourth tick
fourth tick
Answered by
FLu
Anyone for Problem 5?
Answered by
Anonymous
problem 5 plz
Answered by
rih thks!!!
answer to P5 ?
Answered by
Mat
Answer for Question 5 please?
Answered by
Tun
Yes please question 5 anyone?
Answered by
Anonymous
qwerty this is for you.
5a......
5b 1-2/K -2/K
5c 2/K-1 -2/K
I have no idea what i am doing wrong with the a part. If u do get it let me know. Thanks....WU
5a......
5b 1-2/K -2/K
5c 2/K-1 -2/K
I have no idea what i am doing wrong with the a part. If u do get it let me know. Thanks....WU
Answered by
Anonymous
LOL qwerty for you
cant believe i just got it
5a -2/K+1
2/K
cant believe i just got it
5a -2/K+1
2/K
Answered by
dal
I don't know who are you, but thank you!
Answered by
Anonymous
@ dal You can just call me Wu
And you are welcome.
If you have made it this far you deserve the joy.
@ qwerty please make sure u got this too.
And you are welcome.
If you have made it this far you deserve the joy.
@ qwerty please make sure u got this too.
Answered by
FLu
Thanks, that's great!
Answered by
FLu
Anonymous check circuit question, I have given the answer!
Answered by
xaad
love u anonymous ..
Answered by
FLu
Does anyone know this?
Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV? Ignore possible relativistic effect
I have b) 500
Anyone for a) and c)?
Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV? Ignore possible relativistic effect
I have b) 500
Anyone for a) and c)?
Answered by
Im Anononous
13 c) 0 13 d) 0
Answered by
My
Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV?
Answered by
Uer
A current I travels counterclockwise through a closed copper wire loop which has the shape of a rectangle with sides a and b.
What is the magnitude of the magnetic field at the center, C , of the rectangle? Express your answer in terms of a, b, I and mu_0. (Enter mu_0)
What is the magnitude of the magnetic field at the center, C , of the rectangle? Express your answer in terms of a, b, I and mu_0. (Enter mu_0)
Answered by
Rad
Thanks FLu!
Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV?
Can somebody help with a) and c) please?
Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV?
Can somebody help with a) and c) please?
Answered by
FLu
Found c)
Anyone for a) please?
Anyone for a) please?
Answered by
chepe
problem 6 plz
Answered by
Anonymous
6) 1
Answered by
elviria
does anyone have the answer for problem 1b and c
Answered by
TriCk
Answer of problem 1b is 1
and 1c is a,-b
and thanku very much anonymous and Flu....
and 1c is a,-b
and thanku very much anonymous and Flu....
Answered by
Stud
Hey, Wu (Anonymous). Need help with qwerty's question here: site name/display.cgi?id=1366086762
Any help will be appreciated :)
Any help will be appreciated :)
Answered by
rare
someone please ans 12a..-1,3 is showing wrong..please help
Answered by
Anonymous
@rare: i have the same problem..
Answered by
ss01
Consider a qubit subject to the Hamiltonian (1 4
4 1).
Calculate the states of definite energy. What are the energies of these states?
4 1).
Calculate the states of definite energy. What are the energies of these states?
Answered by
Anonymous
12
-3,5
-3,5
Answered by
aga
Can someone tell me the answer of Q.11?
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