Question

Suppose we ran m steps of Grover's algorithm on some function f (which has one marked element y) and the resulting superposition was exactly |y>.

(a) What was the state after the (m−1)th step? Note that you can describe the superposition by specifying two numbers, αy and αx for x≠y. Use K to denote the total number of elements. Please fully simply your answer.
Answer in this format: αy: αx for x≠y:

(b) Now, if we run one more step (total of m+1 steps), what is the resulting superposition?
Answer in this format: αy: αx for x≠y:

(c) What if you now apply another phase inversion?
Answer in this format: αy: αx for x≠y:

Answers

s
PLS HELP
Anonymous
help guys
My
Anyone please?
Anónimo
So the state is at |y> after m steps. So the probability of getting that is 1 and the rest is 0. So What is the mean and what if we move 1 step forward? Is the the same as moving 1 step back?
horseman
I have tried to solve it through the trigonometrics way. If in the iteration m you have probability 0 for the rest of the situations, then cos[(2k+1)g] = 0 becasuse of that k=(pi/(4*g))-(1/2) and you know that cos(g)=sqrt(k-1)/sqrt(k) so you have the value of k and the value of cos(g) so you can apply it to k-1 and try to solve the values of coefficients with the aid of the trigonometrics functions. However the marker gives me a red cross, I don´t know what I´m doing wrong! Please help.
Anonymous
Problem 4,5,10,11 answers guys
Anonymous
12 a and 13 a also pls guys
FLu
Problem 10
1; -1
-1; 1

Problem 11
0000
0000
0010
0001

Anyone for Problem 4 and 5 please?
Anonymous
Thanks flu
FLu
No prob anynomous.
Problem 13 a
1; 0
0; 5
Problem 12 a
-1, 3

Would be nice if someone could figure out 4 and 5.
Maverick
12(a) The answer is −1,3

The states of definite energy and their energy are given by the eigenvectors and eigenvalues of the Hamiltonian. In this case, the eigenvectors are |+> and |−> with eigenvalues 3 and −1 respectively.
Anonymous
Thank you all.
And does anyone can help me with p1,p5 and p13
FLu
Problem 1
a)No
b)1
c)a; -b

Problem 13
a)
1; 0
0; 5

b)Last tick for multiple question

c)0
d)0

Anyone for Problem 5 though please?
Mur
Yes, anyone for Problem 5 please!
rih
Problem 6 please!
Anne
For the problem 6 the solution is "1"

Anyone tried the problem 5?
plz help
please guys problem 5

Thank you so much!!
hi guys solution for Problem 4 and 5? PLease
rih
problem 4
- 1/sqrt(8) ,1/sqrt(8)
- - 1/sqrt(8) , 1/sqrt(8)
- 5/(2*sqrt(8), 1/(2*sqrt(8)
- -5/(2*sqrt(8)) , 1/(2*sqrt(8))
- 11/(4*sqrt(8)), -1/(4*sqrt(8))
problem 5 ???????
FLu
Yes guys, Problem 5 please?
Gyanno
12b please and 5?
FLu
12)b
fourth tick
FLu
Anyone for Problem 5?
Anonymous
problem 5 plz
rih thks!!!
answer to P5 ?
Mat
Answer for Question 5 please?
Tun
Yes please question 5 anyone?
Anonymous
qwerty this is for you.

5a......

5b 1-2/K -2/K

5c 2/K-1 -2/K


I have no idea what i am doing wrong with the a part. If u do get it let me know. Thanks....WU
Anonymous
LOL qwerty for you

cant believe i just got it

5a -2/K+1
2/K
dal
I don't know who are you, but thank you!
Anonymous
@ dal You can just call me Wu
And you are welcome.
If you have made it this far you deserve the joy.

@ qwerty please make sure u got this too.
FLu
Thanks, that's great!
FLu
Anonymous check circuit question, I have given the answer!
xaad
love u anonymous ..
FLu
Does anyone know this?

Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV? Ignore possible relativistic effect

I have b) 500

Anyone for a) and c)?

Im Anononous
13 c) 0 13 d) 0
My
Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV?
Uer
A current I travels counterclockwise through a closed copper wire loop which has the shape of a rectangle with sides a and b.
What is the magnitude of the magnetic field at the center, C , of the rectangle? Express your answer in terms of a, b, I and mu_0. (Enter mu_0)
Rad
Thanks FLu!

Consider a deuteron in a cyclotron with field strength 0.5T. The deuteron is accelerated twice per rotation by a potential of V=25 kV. (a) If the radius of the cyclotron is 2 meter, what is the maximum energy of the deuteron? Express your answer in Joules (the deuteron mass is 3.34×10−27kg) b)Starting from a negligibly small velocity, how many full rotations does the deuteron need before it reaches this maximum energy? c) What is the time it takes for the deuteron to make one complete rotation when its energy is about 500 keV and when it is about 5 MeV?

Can somebody help with a) and c) please?
FLu
Found c)

Anyone for a) please?
chepe
problem 6 plz
Anonymous
6) 1
elviria
does anyone have the answer for problem 1b and c
TriCk
Answer of problem 1b is 1
and 1c is a,-b
and thanku very much anonymous and Flu....
Stud
Hey, Wu (Anonymous). Need help with qwerty's question here: site name/display.cgi?id=1366086762

Any help will be appreciated :)
rare
someone please ans 12a..-1,3 is showing wrong..please help
Anonymous
@rare: i have the same problem..
ss01
Consider a qubit subject to the Hamiltonian (1 4
4 1).
Calculate the states of definite energy. What are the energies of these states?
Anonymous
12
-3,5
aga
Can someone tell me the answer of Q.11?

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