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honors student
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9. B) m∠B = 55.5°; E) m∠B = 124.5° 10. D) 45.8°
i just took the test and the correct answer is wavelength of the stationary source: 11.25 ft; perceived wavelength: 9.25 ft
tysm weakinsomniac, still correct for honors as of 3/31/2022 :)
BEP is 100% right for honors students: 5) both position and velocity
thank you, 100%! be careful with 4, i got it wrong cause i misread the correct answer
B) f(x) = 3e^(x+6)-4 and D) f(x) = 3(x+6)^2-4
A) -tan (-theta) and D) tan (theta + 2pi)
1. C (28.3) 2. E (sec x) 3. B (tan x and sec x) 4. E (sec x) 5. A (2.5 seconds) 6. D (a=1; b=-1; c=pi) 7. C (f(x)=2sin(-1.5x+0.5)-2) 8. B (theta(t)=6cos(2pi/3 t) 9. C (x=[20,30]) 10. A (a decreasing function defined in Quadrants I and II) 11. B (51°) 12.
1. C (28.3) 2. E (sec x) 3. B (tan x and sec x) 4. E (sec x) 5. A (2.5 seconds) 6. D (a=1; b=-1; c=pi) 7. C (f(x)=2sin(-1.5x+0.5)-2) 8. B (theta(t)=6cos(2pi/3 t) 9. C (x=[20,30]) 10. A (a decreasing function defined in Quadrants I and II) 11. B (51°) 12.
1. C (28.3) 2. E (sec x) 3. B (tan x and sec x) 4. E (sec x) 5. A (2.5 seconds) 6. D (a=1; b=-1; c=pi) 7. C (f(x)=2sin(-1.5x+0.5)-2) 8. B (theta(t)=6cos(2pi/3 t) 9. C (x=[20,30]) 10. A (a decreasing function defined in Quadrants I and II) 11. B (51°) 12.
1. B (f(x)=4cos(x/2)-3) 2. B,F,G (c=-1; a=2; b=2) 3. C (H(t)=-2.4cos(0.017t)) 4. A,B,E,F (y=cos^-1x; y=cot^-1x; y=sin^-1x; y=tan^-1x) 5. C (y=sin^-1x) 6. C (48.7°) 7. C (f(g(x))=sec(sinx); domain: all real numbers; range: 1
sike no it ain't
b is correct
for honors: 1. D (4pi) 2. B, D (cot(-θ)=-cot(θ)), (cot(θ+pi)=cot(θ) 3. A, B (f(x)=csc x), (f(x)=1/sin x)
for honors 1. a (sqrt5/2) 2. a (b=7.2, c=9.3) 3. b (0.4) 4. a (22°) 5. a (37.5 mi.) 6. c ([11pi]/9) 7. b (200°) 8. c (13.5 cm) 9. c (-3/5) 10. a (sqrt2/2) 11. c (sqrt3/3) 12. b (1) 13. b (pi/4) 14. a (-1/2) 15. d (IV) 16. d (undefined)
it's 22°
(-ထ, 5) U (5, ထ)
it's actually D. 3.204 x 10^-17 joules
1. D) The sequence diverges; the series diverges 2. D) geometric, divergent 3. C & E) a geometric sequence with r = (3/5) ; a geometric sequence with r = -(1/6) might be different for non-honors
for honors: 1. Computers carry out the exact instructions you give them, whether they are the correct instructions or not. 2. The effects of the simplifications are often relatively small, the computations may become too complex if all factors are
steve is right! thank you steve!
C) f(x) approaches infinity as x approaches negative infinity and f(x) approaches negative infinity as x approaches infinity
C) 38.7 kg
A) Gravitational force is negative because it is attractive.
C) the apple and Earth
1) 0.10 A 2) 4.0 A 3) The current through all of the resistors will *add up to* 10 A. 4) 20 V 5) The voltage drops across both R1 and R2 will be 10 V each.
for honors: 5. series
3. B and D -- f(x)=(x+1)(x-3)(x-5)^5 and f(x)=(x+1)^7(x-3)^3(x-5)^4 4. B and C -- f(x)=3x^4-10x^3-x-7 and f(x)=-x^5+4x^3-2x^2-3x+7 :)
1. momentum 2. an arrow 3. p = m*v 4. the total momentum is CONSERVED 5. 6.0
The farmer could increase the torque, making it easier to grind, by moving the handle further away from the point of rotation.
B) The drag on the helicopter is directed downward and to the south.
B) The acceleration decreased to *a quarter* of its original value, or about 0.13 m/s^2.
C) The ratio of net force to mass is constant across all objects.
it's actually mass.
The net force causes a decrease in acceleration because without the force, the ball's movement would remain the same.
the force of gravity causes the raindrops to accelerate
The cart will move to the right.
^^ simple version of what steve said: even tho the x-value "0" appears twice, it doesn't count because it has the same y-value, so they overlap each other. so if you were to graph it, you would only see 3 points, even tho there are really 4.
this is my favorite website
accurate as of may 2021 full test for honors: 1. D (4) 2. A (0) 3. D (CnH2n+2) 4. C (the electron...) 5. C (octane) 6. C (alkyne) 7. C (2-methylpropane) 8. C (rings with 5 or 6 carbon atoms) 9. C (peat) 10. D (distillation) 11. A ( Cl --
