digforbear

This page lists questions and answers that were posted by visitors named digforbear.

Questions

The following questions were asked by visitors named digforbear.

Answers

The following answers were posted by visitors named digforbear.

use the quotient rule h(x)=&#131(x)/g(x) h&prime(x)=[&#131 &prime (x)*g(x) - g&prime (x)*&#131 (x)]/g(x)<sup>2</sup>

first 121 km/h (1000m/1km)(1h/3600s) = 33.6 m/s v<sub>f</sub><sup>2</sup> = v<sub>i</sub><sup>2</sup> + 2a(&Delta x) &Delta x is what we want to solve for, it tells us the distance which we will compress the barrier so it needs to be atleast that thick a...

not enough information to answer the question... acceleration? if there is no acceleration then: x-x<sub>o</sub> = v<sub>o</sub>t x = 100m

the exact formula for this should be in your text book

5.3sin(8.4) make sure your calculator is in DEG<sup>o</sup> mode