Asked by Sasha
Highway safety engineers build soft barriers such as the one shown in Figure 3-21, so that cars hitting them will slow down at a safe rate. A person wearing a safety belt can withstand an acceleration of -3.0 102 m/s2. How thick should barriers be to safely stop a car that hits a barrier at 121 km/h?
Answers
Answered by
brittany ad
almost 2 feet in width
Answered by
digforbear
first 121 km/h (1000m/1km)(1h/3600s) = 33.6 m/s
v<sub>f</sub><sup>2</sup> = v<sub>i</sub><sup>2</sup> + 2a(&Delta x)
&Delta x is what we want to solve for, it tells us the distance which we will compress the barrier so it needs to be atleast that thick
a is the max acceleration given which I don't really understand from what you've written (-3.0 102?)
v<sub>f</sub> is 0 because the car will stop
v<sub>i</sub> is 33.6 m/s
solving for &Delta x we get
[v<sub>f</sub><sup>2</sup> - v<sub>i</sub><sup>2</sup>] / 2a = &Delta x
v<sub>f</sub><sup>2</sup> = v<sub>i</sub><sup>2</sup> + 2a(&Delta x)
&Delta x is what we want to solve for, it tells us the distance which we will compress the barrier so it needs to be atleast that thick
a is the max acceleration given which I don't really understand from what you've written (-3.0 102?)
v<sub>f</sub> is 0 because the car will stop
v<sub>i</sub> is 33.6 m/s
solving for &Delta x we get
[v<sub>f</sub><sup>2</sup> - v<sub>i</sub><sup>2</sup>] / 2a = &Delta x
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