Steve ®

This page lists questions and answers that were posted by visitors named Steve ®.

Questions

The following questions were asked by visitors named Steve ®.

Answers

The following answers were posted by visitors named Steve ®.

If you can help a student, why would you get into trouble? Nice work, by the way.

P = kv^3 So, P/v^3 is constant. You want P such that P/12^3 = 500/10^3

0.68 = 68/100 = 17/25

If x is at 3%, then .03x + .02(25000-x) = 600 Having found x, then the two accounts hold 1.03x and 1.02(25000-x)

Nice try, Stevie boy.

If you draw the figure, you will see that the ellipse has semi-major axis of 30+40=70 So, the equation of the ellipse is x^2/70^2 + y^2/b^2 = 1 Since (30,30) is on the ellipse, 30^2/70^2 + 30^2/b^2 = 1 b = 21√(5/2) The area of the ellipse is thus A = πab...

well, 17.9/h = cos18.5° now just solve for h

I don't see a series. I do see a <b>-=</b> which I cannot decode. And what does <b>1 (2n+1)</b> mean? Use ^ for exponents, as in 2^n or (-1)^(n-1) Use parentheses if needed 1/n+2 is not the same as 1/(n+2)

Did you even check out your idea? a(1) = 0 a(2) = a(1) + 2^2-3 = 0+1 = 1 a(3) = a(2) + 2^3-3 = 1+5 = 6 a(4) = a(3) + 2^4-3 = 6+13 = 19

just add up the angles... 15+2(2x+4) = 83

If the neighbor gets x, then the friend gets 2x and you get 4x