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RZeal
Questions (4)
3HClO2(aq) +2Cr3+(aq) + 4H2O(l) -> 3HClO(aq) + (Cr2O7)2–(aq) + 8H+(aq)
At pH 0.00, with [Cr2O72–] = 0.80 M, [HClO2] = 0.15 M,
4 answers
850 views
Calculate the Ecell for this reaction
3HClO2(aq) +2Cr3+(aq) + 4H2O(l) -> 3HClO(aq) + (Cr2O7)2–(aq) + 8H+(aq) I thought Cr + e
1 answer
705 views
Consider a 0.42 M solution of NaCH3COO
CH3COO–(aq) + H2O(l) -> CH3COOH(aq) + OH–(aq) Calculate the pH of the solution at
1 answer
726 views
Enough of a monoprotic acid is dissolved in water to produce a 0.0165 M solution. The pH of the resulting solution is 2.38.
2 answers
1,850 views
Answers (4)
Thanks I was able to solve it!
Sorry about the confusion Ecell = 0.15 and Eocell = 0.31
Ka = Ch3COO- 5.6x10^-10 Ka = Ch3COOH 1.8x10^-5
Nevermind I figured it out, With the equation Ka = x^2 / 0.0165 - x x = [H+] I forgot to do the 0.0165-x in my original calculation, but after doing that I got the correct answer.
