Questions and answers by

Mary Ruth

Questions (5)

In a titration, 54.5 mL of 0.6 M hydrochloric acid solution is needed to neutralize 78 mL of potassium hydroxide. What is the
1. 2 answers
2. 329 views
Calculate the pH of a 1,638 mL solution containing 0.45 moles of carbonic acid
1. 4 answers
2. 221 views
Calculate the pH of a 5.942 mL solution containing 1.1 g of nitric acid
1. 5 answers
2. 261 views
A 80 mL sample of sulfuric acid solution is neutralize by 254.4 mL of a 1.3 M aluminum hydroxide solution. What is the molarity
1. 6 answers
2. 303 views
What is the molarity of a calcium hydroxide solution if 29.52 mL of 0.4 M nitric acid is needed to neutralize 0.046 L
1. 2 answers
2. 304 views

3H2SO4 + 2Al(OH)3 ==> Al2(SO4)3 + 6H2O .2545 L x 1.3M 2Al(OH)3 = .33085 mol .33085 mol x (1 mol H2SO4/2 mol ) / .080L H2SO4=4.14
Ugh. I used the wrong stuff and did something with sodium
H2SO4 + 2NaOH = 2H2O + Na2SO4 .2545 L NaOH x 1.3M NaOH = .33085 mol NaOH .33085 mol NaOH x (1 mol H2SO4/2 mol NaOH) / .080L H2SO4=4.14
I used an online calculator. Our teacher didn't explain this well on how to work pH
I used an online calculator. Our teacher didn't explain this well on how to work pH
It is 0.2 M?
Is it 4.14?
Is it 0.42?
Is it 2.53?
Is it 3.46?
actually, it's 5,942 mL not 5.942

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