Question

What is the molarity of a calcium hydroxide solution if 29.52 mL of 0.4 M nitric acid is needed to neutralize 0.046 L
It is 0.2 M?
Ca(OH)2 + 2HNO3 ==> 2H2O + Ca(NO3)2
mols HNO3 = M x L = 0.4 x 0.02952 = 0.01181
Convert mole HNO3 to moles Ca(OH)2. 0.01181/2 = 0.005905
M Ca(OH)2 = moles/L = 0.005592 moles/0.046 L = 0.1283 M

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