MWLevin (aka Marth)
This page lists questions and answers that were posted by visitors named MWLevin (aka Marth).
Questions
The following questions were asked by visitors named MWLevin (aka Marth).
Answers
The following answers were posted by visitors named MWLevin (aka Marth).
Let θ be the angle between a and b. We know that cosθ = (a∙b) / (|a||b|). Since a and b are unit vectors, |a|=|b|=1. Therefore we need to find a∙b. a+2b and 5a-4b are perpendicular, so (a+2b)∙(5a-4b)=0 Multiply this out to obtain 5a∙a + 6a∙b - 8b∙b = 0 wh...
9 years ago
Depending on the formula, 3 answers could be correct. If the formula is sum(A1:A7), copying it to C8 will result in sum(C1:C7). If the formula is sum($A1:$A7), copying it to C8 will result in sum($A1:$A7). If the formula is sum($A1:A7), copying it to C8 w...
9 years ago
Take the derivative of each to find the rates of growth. f'(x) = 1 + cos(x) g'(x) = 1 lim_{x→∞} g'(x) = 1 but lim_{x→∞} f'(x) does not exist because cos(x) varies between -1 and 1. Therefore, the rates of growth cannot be compared.
9 years ago
It's asking for the second derivative. The first derivative is ln(t^2) evaluated at 3x; you need to differentiate again to get the second derivative.
9 years ago
Use the first equation to find s in terms of x, then substitute into the second equation.
9 years ago
"I also graphed the absolute value function and the area under the interval [0,2] is kind of in two different separate regions." Good. You have to separate it into two integrals for each region. For x < 0.5, |2x-1| = 1-2x. For x >= 0.5, |2x-1| = 2x-1. Int...
9 years ago