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MWLevin (aka Marth)

Answers (6)

"I also graphed the absolute value function and the area under the interval [0,2] is kind of in two different separate regions." Good. You have to separate it into two integrals for each region. For x < 0.5, |2x-1| = 1-2x. For x >= 0.5, |2x-1| = 2x-1.
Use the first equation to find s in terms of x, then substitute into the second equation.
It's asking for the second derivative. The first derivative is ln(t^2) evaluated at 3x; you need to differentiate again to get the second derivative.
Take the derivative of each to find the rates of growth. f'(x) = 1 + cos(x) g'(x) = 1 lim_{x→∞} g'(x) = 1 but lim_{x→∞} f'(x) does not exist because cos(x) varies between -1 and 1. Therefore, the rates of growth cannot be compared.
Depending on the formula, 3 answers could be correct. If the formula is sum(A1:A7), copying it to C8 will result in sum(C1:C7). If the formula is sum($A1:$A7), copying it to C8 will result in sum($A1:$A7). If the formula is sum($A1:A7), copying it to C8
Let θ be the angle between a and b. We know that cosθ = (a∙b) / (|a||b|). Since a and b are unit vectors, |a|=|b|=1. Therefore we need to find a∙b. a+2b and 5a-4b are perpendicular, so (a+2b)∙(5a-4b)=0 Multiply this out to obtain 5a∙a + 6a∙b -

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