why not doing it the actual way ????
∫ ln(t^2) dt
= t ln(t^2) - 2t | from ??????
you have a = 1 to b = 3x
are a and b the lower and upper values ?
if so,
= 3x ln (9x^2) - 6x - (0 - 2)
= .....
How would I set this up in my calculator?
Let F(x)=∫ ln(t^2) dt where a= 1 and b=3x . Use your calculator to find F"(1).
I set it up and I got way the wrong answer. I got 2ln(1)=0
4 answers
I don't know because that's what the question says. Thanks
Yes and b are the lower and upper and I plugged in my value of 1 and got 2.59 but that's not one of my answers. My options are
12
6
4
1/9
12
6
4
1/9
It's asking for the second derivative. The first derivative is ln(t^2) evaluated at 3x; you need to differentiate again to get the second derivative.