KokkoDeRas

This page lists questions and answers that were posted by visitors named KokkoDeRas.

Questions

The following questions were asked by visitors named KokkoDeRas.

Answers

The following answers were posted by visitors named KokkoDeRas.

50*1.15=57.5, 70-57.5=12.5

i set the equation end give you the solutions but you try to get there x=first test, y=second test z= three test i)second test score was 8 points higher than her first score => y=x+8 ii)Her third score was 88=> z=88 iii)B average (between 80=> B=(x+y+z)/3...

sorry.....errata corrige: iii)B average (between 80=> B=(x+y+z)/3>80 iiii)B average...and 89 inclusive)=> B=(x+y+z)/3<89

i do not know if this is process you'll be fine. after finding the spatial coordinates of tha sobstitute in the distans equation between two points: first aircraft angle a1=24.5*2Pg/360=0.43Rad second aircraft angle a2=16.0*2Pg/360=0.28Rad first aircraft...

i do not know if i uderstand the question but i'll try: money Fariq call them x Edward money x+40 If Edward gives 1/5 of his money to Fariq => Fariq as x+ 1/5 Edward money(x+40)/5, Fariq as x+(x+40)/5 i did not understand if Fariq has 7/8 of the money tha...

to solve this problem we need trigonometry therefore takes the radiant 67°*3,14/180=1,17 rad.= a point P=50m height tower H=? L=hypotenuse of the right triangle LPH P=Lcos(a)=> (i)L=p/cos(a) (ii)H=Lsen(a) (i)+(ii)H=[p/cs(a)]*sn(a) tan(a)=sn(a)/cs(a)===>H=...

e)1 only with whole cube root

i) i suppose that the water behaves like a solid so the force of the water, componentY, is m*g=65kg*9.81m/s2 ii) the force the water is only vertical and vanishes with the weight force(if no sinks or flies) iii)Component X is 0 the water-skier feels only...

the test gives you the possible number of smaller cubes [a)4 b)16 c)1/4 d)-1/5 e)1] they must be the solutions the cube root of an integer, example [a)4 b)16 c)1/4 d)-1/5 e)8] smaller cubes (e)8 cube 2 2*2*2=8 1*1*1=1

for Ms.Sue I understand but you have to choose an answer ... but maybe I'm wrong For jhonn YES

sorry.....yes, the 4h-1 is on top of 1+h explain what?

you need to know if h>0

strange way to write an equation! i) 30x+10x=40 => 40x=40 => x=40/40; x=1 ii) 16x+8=40 => 16x=40-8 => x=32/16; x=2 ...perhaps

i forgot to specify in ii) x=-b/(2a) => 2=-b/(2a)

F d -inf;+inf r [-19;+inf[ Y d -inf;+inf r [-3;+3] G d -inf;+inf r ]0;+inf[

i)the area of rectangle is x*y (whit x,y side)=>x*y=3200 Ya^2 ii)the condition imposed from the questions is: x+y+y=200 Ya (i have choise two y because the text not exsplicit the misure of one the side): x+2y=200 => x=200-2y Ya for (i) (200-2y)*y=3200 Ya^...

x=vt+(1/2)*a*(t)^2 x=7*15-(1/2)*4*(15)^2