Asked by Don
I need help with the following problem: From a point 50 meters from the bottom of a radio tower along level ground, the angle of elevation to the top of the tower is 67 degrees. What is the height of the tower?
Answers
Answered by
Steve
think back, back, back to your days in trig.
If the tower has height h,
tan 67 = h/50
h = 117.8 m
If the tower has height h,
tan 67 = h/50
h = 117.8 m
Answered by
KokkoDeRas
to solve this problem we need trigonometry therefore takes the radiant
67°*3,14/180=1,17 rad.= a
point P=50m
height tower H=?
L=hypotenuse of the right triangle LPH
P=Lcos(a)=> (i)L=p/cos(a)
(ii)H=Lsen(a)
(i)+(ii)H=[p/cs(a)]*sn(a)
tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m
67°*3,14/180=1,17 rad.= a
point P=50m
height tower H=?
L=hypotenuse of the right triangle LPH
P=Lcos(a)=> (i)L=p/cos(a)
(ii)H=Lsen(a)
(i)+(ii)H=[p/cs(a)]*sn(a)
tan(a)=sn(a)/cs(a)===>H=p*tan(a)=118m
Answered by
Maurice
From my view. Tan=opp/adj
Therefore when u cross multiply u have
50tan67
H=82.6m
Approx. 83m
Therefore when u cross multiply u have
50tan67
H=82.6m
Approx. 83m
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