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Jamie-anne
Questions (1)
Calculate the pH of:0.01M HCl pH=-log[H*]. ..=-log[0.01]. ..=2.is the pH of HCl,I enter -log on my calculator Igot 2 as my
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Answers (3)
pH=-log[H*]. =-log[0.01] =2 I've used my calculator by entering -log in brackets 0.01 and I got 2 as my answer,Am I using the right step of formular?I'm not sure about my answer because of pH 14 in front of a solution of hydrogen,ph=-log[H*] poH=14-pH
0.01M HCl.................... pH=-log[H*]........ ..=-log[0.01]................ ..=2. I used my calculator to enter the above problem and my answer is 2.Am I using the right formular??I'm not sure about that formular because of pH14 infront of a
H2SO4 + K=====>KSO4 + H2. Ionic equation:..... H2SO4 + K*===>K*(aq) +SO4(aq)+H2. Net eqn. H2SO4===>SO4^2- + H2........I'm confused because I've Cross 2(K*),but not satisfied with the net ionic equation.Please could someone help me recheck my answer?
