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Use Dilution Equation (M1V1 = M2V2) to solve this problem. M1=1.00mols/L M2=? V1=150.0mL, convert to Liter V1=150mL*(1L/1000mL)=.15L Do the same to V2 V2=750.0mL(1L/1000mL)=.75L plug in the numbers into the Equation M1V1=M2V2 M2=M1V1/V2,
M = 0.250 mols/L * (111g CaCl2/1 mols CaCl2)= 27.7g/L n = M*L n = (27.7g/L)*(5.5L)= 153g of CaCl2