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A chemist wants to make 4.5 L of a 0.310 M CaCl2 solution what mass of CaCl2 (in g) should the chemist useAsked by Lisa
A chemist wants to make 5.5 L of a 0.250 M CaCl2 solution, what mass of CaCl2 (in g) should the chemist use?
Answers
Answered by
bobpursley
massCaCL2=molarity*volume*molmassCaCl2
Answered by
Stacy
Wha??
Answered by
Dmam
M = 0.250 mols/L * (111g CaCl2/1 mols CaCl2)= 27.7g/L
n = M*L
n = (27.7g/L)*(5.5L)= 153g of CaCl2
n = M*L
n = (27.7g/L)*(5.5L)= 153g of CaCl2
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