Daoine

This page lists questions and answers that were posted by visitors named Daoine.

Questions

The following questions were asked by visitors named Daoine.

Answers

The following answers were posted by visitors named Daoine.

So Anonymous you got 964.29 N??
11 years ago
jennifer for b I was thinking if we know N = ft and we derive this wouldn't it be the same f? I mean dN/dt = d(f*t)/dt that results in f. The other idea I had was calculating the wavelenght (lambda = v/f) using the sound velocity and the given f and then...
11 years ago
Are you sure about a?
11 years ago
I did pretty much the same of what you're showing and I got a) 25, b) 2.5 and c) 0.64 I haven't check it yet because it is my last submission and I want to be sure.
11 years ago
guys a is 25 for sure
11 years ago
I think that the fecuency remains the same in D. Because source and observer are at rest. By the same I mean that it could be 650 or the one you at c.
11 years ago
Look ellie you're right about b and c and d is 650 =)
11 years ago
I already got a and b but for c I thought that by equilibrium C will be the same as a, I'm confused could you give me a hint? Thanks.
11 years ago
Well remember the work energy theorem First m1 has potencial energy mgR then it starts moving such as the block m1gR=1/2m1v(square2) + 1/2m2v(square2)
11 years ago
Can anyone please explain the logic of the problem, not a solution a hint.
11 years ago
dT/dh= - ƴ/(ƴ-1) Mg/Nk with ƴ/(ƴ-1) as a constant is what I remember of the temperature as a function of time. Still I can't comprehend entirely the problem.
11 years ago
I think we have to find out ƴ ant then use dp/p= ƴ/(ƴ-1) dT/T
11 years ago
I got a and c but the time is breaking my brain in 2. Any ideas?
11 years ago
asha which was your pressure value at a?
11 years ago