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Daoine
Questions (1)
Consider the spring - mass system, shown in Figure 4.2.4. consisting of two unit masses suspended from springs with spring
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Answers (14)
asha which was your pressure value at a?
I got a and c but the time is breaking my brain in 2. Any ideas?
I think we have to find out ƴ ant then use dp/p= ƴ/(ƴ-1) dT/T
dT/dh= - ƴ/(ƴ-1) Mg/Nk with ƴ/(ƴ-1) as a constant is what I remember of the temperature as a function of time. Still I can't comprehend entirely the problem.
Can anyone please explain the logic of the problem, not a solution a hint.
Well remember the work energy theorem First m1 has potencial energy mgR then it starts moving such as the block m1gR=1/2m1v(square2) + 1/2m2v(square2)
I already got a and b but for c I thought that by equilibrium C will be the same as a, I'm confused could you give me a hint? Thanks.
Look ellie you're right about b and c and d is 650 =)
I think that the fecuency remains the same in D. Because source and observer are at rest. By the same I mean that it could be 650 or the one you at c.
guys a is 25 for sure
I did pretty much the same of what you're showing and I got a) 25, b) 2.5 and c) 0.64 I haven't check it yet because it is my last submission and I want to be sure.
Are you sure about a?
jennifer for b I was thinking if we know N = ft and we derive this wouldn't it be the same f? I mean dN/dt = d(f*t)/dt that results in f. The other idea I had was calculating the wavelenght (lambda = v/f) using the sound velocity and the given f and then
So Anonymous you got 964.29 N??
