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Questions (1)
How many mL of a 0.5M Ca(OH)2 solution are needed to neutralize 38 mL of a 2M HNO3 solution?
ANSWER IS: x = multiply / = divide
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Answers (1)
ANSWER IS: x = multiply / = divide 38mL HNO3 X 1 L HNO3 x 2M HNO3 x 1 L Ca(OH)2 x 2M Ca(OH)2 x 1000 mL / 1000 mL/1L HNO3/..5mL Ca(OH)2/1M HNO3/1L = 304 mL Ca(OH)2
