AmbiguousCase

85.0 mL of 1.50 mol/L ammonium chloride solution is added to 250 mL of water. Calculate the molar concentration of the final solution The answer on the sheet says 0.381 mol/L but I keep getting 0.51

Solve cos315*cos(-390)-sin225*sin750 cos315: <RA = 360-315 = 45 cos45 = 1/√2 cos-390: <RA=-390+360 =30 cos30= √3/2 sin225: <RA = 225-180 = 45 Sin45=1/√2 Sin750: <RA = 750 - 2(360) =30 Sin30=1/2 Put it all together... (1/√2)(√3/2)-(1/√2)(1/2) =√3/2√2 - 1/2...

85.0 mL of 1.50 mol/L ammonium chloride solution is added to 250 mL of water. Calculate the molar concentration of the final solution How would I do this, given 2 volumes?

Thanks^