Question
85.0 mL of 1.50 mol/L ammonium chloride solution is added to 250 mL of water. Calculate the molar concentration of the final solution.
Using the formula C(Concentration)=n(moles)/v(Volume measured in litres.)
How am I supposed to solve this question given two volumes?
Using the formula C(Concentration)=n(moles)/v(Volume measured in litres.)
How am I supposed to solve this question given two volumes?
Answers
use M1V1=M2V2
the C=M
That formula is just telling you what concentration is.
In the formula i mention M1 is the initial concentration and V1 is the initial volume. M2 is the final concentration. V2 is the final volume. You are solving for M2.
the C=M
That formula is just telling you what concentration is.
In the formula i mention M1 is the initial concentration and V1 is the initial volume. M2 is the final concentration. V2 is the final volume. You are solving for M2.
Oh, that makes sense. Thanks!
85.0 mL of 1.50 mol/L ammonium chloride solution is added to 250 mL of water. Calculate the molar concentration of the final solution
How would I do this, given 2 volumes?
How would I do this, given 2 volumes?
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