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Ajayb
Answers (21)
How can there be acceleration if the body is moving at constant velocity?
The current through each bulb is the voltage across it divided by its resistance. In this case the bulbs are in parallel and voltage across them is 2.4V.
use the formula: V^2 = U^2 + 2*a*s here, V=0(final speed); U= Initial speed (convert units mi/hr to m/s) a = acceleration s = 108 m Find a in m/s^2 - your answer will be a negative value indicating deceleration.
First find K of the spring: Mg = Kx here, x = elongation of the spring = 13.40 - 12.00 = 1.40 cm = 0.014 m K = Mg/x = 3.15*9.8/0.014 = ?? Having got K, find X from: KX^2/2 = 10.0J where X is the elongation when stored PE is 10.0 Joules. The total length of
The series resistor R should be chosen so as to have a voltage drop of 7.6V(10-2.4)across it. The currents in the two bulbs: i1=2.4/3.0 = 0.8A i2=2.4/2.5 = 0.96A Total current in the circuit = i1+i2 = 1.76A R = 7.6V/1.76A = 4.3 Ohms
(PE+KE)initial = (PE+KE)final mgh + mv0^2/2 = 0 + mv^2/2 => h = (v^2-v0^2)/2g
F = k q^2/r^2 = 9x10^9*1x10^-12/16x10^-4 = 5.6 N 5.6=m*9.8 => m=5.6/9.8=5.7 Kg
Initial momentum of boat+Sally system is=(125+65)*5= 190*5=950 Kg m/s Sally's speed is 2.0m/s relative to boat i.e. w.r.t.a stationary observer it is (2+V)m/s where V is the speed of the boat when Sally walks. Since there is no external force acting on our
Yes, you did it correctly. In order to understand phasor diagram, read your text book. In a purely inductive load, the current lags voltage by 90 deg. In this case (R+L load)the phase angle will be less than 90 - you can find it out once you read the text.
Use PV=nRT to find the pressure of the gas in the container at 20 deg.C. All the variables except for P are given to you in the problem. The heating process is isobaric -so, the pressure would not change. But its volume would increase which you can find by
The kinetic energy of the car will be dissipated as heat due to the frictional forces. KE=(1/2)mV^2=1500*36/2=27000 J The work done by frictional forces=F*d Now, F*d=KE F=KE/d=27000/5=5400 N
The string closest to the axis of rotation would have the maximum tension. Draw the free body diagram and it will be clear that the tension in the closest string balances not only the centrifugal force on the attached ball but also the tension in the
(a) is correct. Force, momentum and velocity are vectors. Energy and work are scalar quantities.
Pressure at the bottom of a water column of height h = d*g*h where, d=density of water(1000Kg/m^3) g=9.8 m/s^2 & h=30 m Calculate P yourself.
You have not mentioned the units in the problem - I trust the mass is 15.5 Kg and Force =38.0 N. Fx= 38*Cos42 .....in hor. direction Fy= 38*Sin42 .....in vertical downward direction For equilibrium in vertical dir.- Normal force N = mg+Fy N=15.5*9.8 +
i=q/t => q=i*t=5.5*120(sec) =660 Coul.
Wi= 1200 rev/min = 20 rev/sec = 20*2*pi rad/sec Wf = 0; alpha= -1.5 rad/s^2 Wf = Wi + alpha*t 0 = 40*pi - 1.5*t t = 40*pi/1.5 = 84 sec Now, theta = Wi*t + (1/2)*alpha*t^2 Plug in the values in this eqn. to get theta - the rotation of the wheel (in
Assume a thermal equilibrium temp. T and find the heat absorbed by ice (say Q1)to raise its temp.from -35 deg. to T deg. Similarly, find heat released by water (say Q2) when its temp. lowers from 45 deg. to T deg. Putting Q1 = Q2 will give you T in deg. C.
Follow the following steps: 1. Calculate the ice block's mass from its volume and density. 2. Compute heat required to raise its temp. from -19.3 degC to 0 deg - Q1 3. Consider latent heat required to change the state from ice at 0 deg. to water at 0 deg.
Q=m*s*T I hope you can compute Q (heat required)
4 rev.= 4*2*pi radians use the formula for angular motion: theta = W0*t + (1/2)*alpha*t^2 .....(1) here theta = 4*2*pi W0 = 4.3 alpha = 3.75 Solve the quadratic eqn.(1)to get the value of t (time) The data on radius of the wheel has no use in solving this
