Question

A driver in a car traveling at a speed of 55.3 mi/h sees a deer 108 m away on the road. Calculate the minimum constant acceleration that is necessary for the car to stop without hitting the deer (assuming that the deer does not move in the meantime).

Answer 1

use the formula:
V^2 = U^2 + 2*a*s

here, V=0(final speed);
U= Initial speed (convert units mi/hr to m/s)
a = acceleration
s = 108 m
Find a in m/s^2 - your answer will be a negative value indicating deceleration.