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consider the following equilibrium. 4NH3(g)
consider the following equilibrium.
4NH3(g) +3O2(g)<-> 2N2(g) + 6H2O(g) suppose 0.30mol of NH3 and 0.40mol of oxygen are added to
2 answers
asked by
Anonymous
1,412 views
Samples of NH3 and 02 are placed in a rigid container. When the equilibrium below is established, the partial pressure of H2O is
2 answers
asked by
Anonymous
3,983 views
Write the expression for the equilibrium constant for the following equation.
4NH3(g)+302(g)=2N2(g)+6H2O(g) K=
1 answer
89 views
4NH3(g)+5O2(g) yield 4NO(g)+6H2O(g)
Deduce the equilibrium constant expression for the reaction.
2 answers
asked by
John
4,819 views
write the equilibrium constant expressions Kp for each of the following
N2O <===> 2NO2 2NO + Br2 <====> 2NOBr 2SO2 + O2 <====>
4 answers
asked by
Taylor
707 views
4NH3(g) + 3O2(g) -> 2N2 + 6H20, K=10^80 @ certain temp
initially, all the reactants and products have concentrations equal to
0 answers
asked by
Daniel
582 views
4NH3(g) + 3O2(g) -> 2N2 + 6H20, K=10^80 @ certain temp
initially, all the reactants and products have concentrations equal to
1 answer
asked by
Daniel
718 views
4NH3(g) + 3O2(g) -> 2N2 + 6H20, K=10^80 @ certain temp
initially, all the reactants and products have concentrations equal to
2 answers
asked by
Daniel
606 views
For the reaction
4NH3(g) + 3O2(g) -> 2N2(g) + 6H2O(g) , K = 10^80 at a certain temperature. Initially, all reactants and products
0 answers
asked by
Eddy
885 views
Consider the reaction below:
4NH3(g) + 3O2(g) -> 2N2 + 6H20, K=10^80 @ certain temp initially, all the reactants and products
2 answers
asked by
Scott L.
694 views