Asked by Anonymous

Samples of NH3 and 02 are placed in a rigid container. When the equilibrium below is established, the partial pressure of H2O is 0.784 atm. What is the partial erasure of NO when the system is at equilibrium?
4NH3 + 5O2 -----> 4NO + 6H2O
Answered by DrBob222
......4NH3 + 5O2 -----> 4NO + 6H2O
I......x......y..........0.....0
C....-4z.....-5z........+4z...+6z
E.....x-4z..y-5z.........4z....6z

pH2O = 6z = 0.784 from the problem
z = ?
Then NO is 4z = ?

Answered by 123
123
There are no AI answers yet. The ability to request AI answers is coming soon!