c2o42-+cr2o72-+cr3++co2(in acid medium)

  1. c2o42-+cr2o72-+cr3++co2(in acid medium)
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    2. ion electron method asked by ion electron method
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  2. Balance the following equations and show the steps:1. MnO4- + C2O42- = Mn2+ + CO2 2. NO2- + MnO4- = NO3- + Mn2+ (in acid
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  3. Balance the following equations:1. MnO4- + C2O42- = Mn2+ + CO2 2. NO2- + MnO4- = NO3- + Mn2+ (in acid Solution) 3. I- + MnO4- =
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  4. ChemistryWhat will happen if hydrochloric acid is added to the following equilibrium system? H+(aq) + 2 CrO42-(aq) ⇔
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  5. ChemistryWhat will happen if hydrochloric acid is added to the following equilibrium system? H+(aq) + 2 CrO42-(aq) ⇔
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  6. Oxalic acid is a relatively strong diprotic acid with Ka1 = 5.6 ´ 10-2 and Ka2 = 5.1 ´ 10-5.What is the oxalate ion, C2O42-,
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    2. Fatima asked by Fatima
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  7. sorry . Can you please help me with this questions If you know?Oxalic acid is a relatively strong diprotic acid with Ka1 = 5.6
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    2. khin asked by khin
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  8. Please check. Thank you.2. What is the reduction half-reaction for the following unbalanced redox equation? Cr2O72– + NH4+
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    2. Jack asked by Jack
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  9. Please explain this to me2I- --> I2 + 2e Cr2O72- ==> Cr3+ 6e + 14H + Cr2O72- ==> 2Cr3+ + 7H20 I don't understand how the left
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    2. Monique asked by Monique
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  10. What is the volume in milliliters of 0.1069 M Cr2O72- required to react with 252.4 mL of 0.08013 M Cl- according to the reaction
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    2. madoo asked by madoo
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