Asked by Monique
Please explain this to me
2I- --> I2 + 2e
Cr2O72- ==> Cr3+
6e + 14H + Cr2O72- ==> 2Cr3+ + 7H20
I don't understand how the left side gets 6 electrons.
2I- --> I2 + 2e
Cr2O72- ==> Cr3+
6e + 14H + Cr2O72- ==> 2Cr3+ + 7H20
I don't understand how the left side gets 6 electrons.
Answers
There are no AI answers yet. The ability to request AI answers is coming soon!