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Yes, because of complex-not real-solutions.

Use the discriminant to determine how many and what kind of solutions the quadratic equation x^2-x=1 has.a)one real solution
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Use the discriminant to determine how many and what kind of solutions the quadratic equation 2x^2 - x = -4 has.a. two complex
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2. 119 views
4x2−3x +2=0 Part 2: Use the discriminant to determine the number of real solutions the equation has.(1 point) Responses 2
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2. 24 views
Part 2: Use the discriminant to determine the number of real solutions the equation has.(1 point) Responses 2 complex solutions
1. 1 answer
2. 13 views
Yes, because of complex-not real-solutions. For instance, if it has two real roots or x-intercepts and two complex conjugate
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2. asked by blobby
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The imaginary numbers are a subset of what type of number(s)?(1 point) Responses complex and real complex and real complex
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2. 31 views
using proper mathematical terminology and different reasoning explain why there are no (as I did not learn complex/imaginary
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2. asked by Logithoid
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How many real solutions does the following quadratic equation have? 4x2+x+3=0 (1 point) Responses two real solutions two real
1. 1 answer
2. 141 views
How many real solutions does the following quadratic equation have? 4x2+x+3=0 (1 point) Responses two real solutions two real
1. 1 answer
2. 325 views
How many real solutions does the following quadratic equation have?4x2+x+3=0 (1 point) Responses three real solutions three real
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2. asked by HaydenReturned
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