Question
Use the discriminant to determine how many and what kind of solutions the quadratic equation 2x^2 - x = -4 has.
a. two complex (nonreal) solutions
b. no real or complex solutions
c. one real solution
d. two real solutions
a. two complex (nonreal) solutions
b. no real or complex solutions
c. one real solution
d. two real solutions
Answers
Answered by
GPT 3.5
To determine the number and type of solutions, we need to calculate the discriminant of the quadratic equation 2x^2 - x = -4. The discriminant is given by the formula:
D = b^2 - 4ac
In this case, the equation is in the form ax^2 + bx + c = 0, where a = 2, b = -1, and c = 4. Substituting these values into the formula, we get:
D = (-1)^2 - 4(2)(-4)
D = 1 + 32
D = 33
The discriminant is positive (D > 0). When the discriminant is positive, the quadratic equation has two distinct real solutions. Therefore, the answer is:
d. two real solutions
D = b^2 - 4ac
In this case, the equation is in the form ax^2 + bx + c = 0, where a = 2, b = -1, and c = 4. Substituting these values into the formula, we get:
D = (-1)^2 - 4(2)(-4)
D = 1 + 32
D = 33
The discriminant is positive (D > 0). When the discriminant is positive, the quadratic equation has two distinct real solutions. Therefore, the answer is:
d. two real solutions
Answered by
oobleck
wrong again!
D = D = (-1)^2 - 4(2)(4) = -31 < 0
so two complex roots
D = D = (-1)^2 - 4(2)(4) = -31 < 0
so two complex roots
Answered by
GPT 3.5
You're right, my apologies for the mistake. The correct calculation for the discriminant is:
D = (-1)^2 - 4(2)(-4) = 1 + 32 = 33
Since the discriminant is positive (D > 0), the quadratic equation 2x^2 - x = -4 has two distinct real solutions. The correct answer is:
d. two real solutions
D = (-1)^2 - 4(2)(-4) = 1 + 32 = 33
Since the discriminant is positive (D > 0), the quadratic equation 2x^2 - x = -4 has two distinct real solutions. The correct answer is:
d. two real solutions