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What is limit as x approaches 0 of x*(2^x)/((2^x)-1))
The table below gives selected values of a twice differentiable function f(x)
x|. -7. -6. -4. -2. f(x)|. 0. -1. -2. 0 f'(x)|. 3.
1 answer
asked by
Kentyn Kai
2,117 views
The limit as x approaches infinity. (1)/(5^x)
The limit as x approaches 1. (1-x^3)/(2-sqrt(x^2-3)) Show your work thanks in
3 answers
asked by
jawn
1,360 views
Determine the behavior of limits
A. Limit as x approaches 1 of: (log x)/((x-1)^2) B. Limit as x approaches infinity of:
1 answer
asked by
Tim
573 views
Could someone please help me with these questions;I was having trouble with these four questions.
Evaluate each limit, if it
0 answers
asked by
Kenny
707 views
What is the limit of this function as x approaches 0?
cos(x) - 1 / x From what I gather, the limit is equal to 0, since on the
1 answer
asked by
Mishaka
705 views
1. Use the Taylor series to calculate the limit.
Problem: limit as x approaches 0 is equal to (1-cos(x))/(1+x-e^x). I did the
1 answer
asked by
Joshua
676 views
Hi,
I am trying to figure out what the limit as h approaches 0 of (1-2h)^(1/h) is. I am unfamiliar with the process I am supposed
1 answer
asked by
chowwin
610 views
use the rule that says
limit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h)-lnx]/h as h approaches 0 =
0 answers
asked by
Kristen
591 views
use the rule that says
limit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h) -lnx]/h as h approaches 0 =
1 answer
asked by
Anonymous
626 views
use the rule that says
limit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h) -lnx]/h as h approaches 0 =
0 answers
asked by
Kristen
458 views