What is limit as x approaches 0 of x*(2^x)/((2^x)-1))

  1. The table below gives selected values of a twice differentiable function f(x)x|. -7. -6. -4. -2. f(x)|. 0. -1. -2. 0 f'(x)|. 3.
    1. answers icon 1 answer
    2. Kentyn Kai asked by Kentyn Kai
    3. views icon 2,117 views
  2. The limit as x approaches infinity. (1)/(5^x)The limit as x approaches 1. (1-x^3)/(2-sqrt(x^2-3)) Show your work thanks in
    1. answers icon 3 answers
    2. jawn asked by jawn
    3. views icon 1,360 views
  3. Determine the behavior of limitsA. Limit as x approaches 1 of: (log x)/((x-1)^2) B. Limit as x approaches infinity of:
    1. answers icon 1 answer
    2. Tim asked by Tim
    3. views icon 573 views
  4. Could someone please help me with these questions;I was having trouble with these four questions.Evaluate each limit, if it
    1. answers icon 0 answers
    2. Kenny asked by Kenny
    3. views icon 707 views
  5. What is the limit of this function as x approaches 0?cos(x) - 1 / x From what I gather, the limit is equal to 0, since on the
    1. answers icon 1 answer
    2. Mishaka asked by Mishaka
    3. views icon 705 views
  6. 1. Use the Taylor series to calculate the limit.Problem: limit as x approaches 0 is equal to (1-cos(x))/(1+x-e^x). I did the
    1. answers icon 1 answer
    2. Joshua asked by Joshua
    3. views icon 676 views
  7. Hi,I am trying to figure out what the limit as h approaches 0 of (1-2h)^(1/h) is. I am unfamiliar with the process I am supposed
    1. answers icon 1 answer
    2. chowwin asked by chowwin
    3. views icon 610 views
  8. use the rule that sayslimit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h)-lnx]/h as h approaches 0 =
    1. answers icon 0 answers
    2. Kristen asked by Kristen
    3. views icon 591 views
  9. use the rule that sayslimit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h) -lnx]/h as h approaches 0 =
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 626 views
  10. use the rule that sayslimit of (e^h - 1)/h = 1 as h approaches 0 to show that the limit of [ln(x+h) -lnx]/h as h approaches 0 =
    1. answers icon 0 answers
    2. Kristen asked by Kristen
    3. views icon 458 views