Titration of 5g of vinegar

  1. The experiment is about titration of vinegar with NaOH. Before I start titration, I need to calculate how much of vinegar I will
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    2. Kim asked by Kim
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  2. Vinegar is a dilute solution of acetic acid. In the titration of 5.00 mL of vinegar, 39.75 mL of 0.137 M sodium hydroxide
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    2. Mark asked by Mark
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  3. A 30.84 cm3 volume of 0.128 M NaOH is required to reach thephenolphthalein endpoint in the titration of a 5.441 g sample of
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    2. Felix asked by Felix
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  4. Vinegar contains acetic acid CH3COOH. Titration of 5.000g vinegar with 0.100M NaOH requires 33.0cm cube to reach the equivalence
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    2. Anonymous asked by Anonymous
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  5. A vinegar contains acetic acid, CH3COOH. Titration of 5.000g of vinegar with 0.100, NaOH requires 33.0 ml to reach equivalent
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    2. Anonymous asked by Anonymous
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  6. a vinegar contains acetic acid,CH3COOH.Titration of 5.00g of vinegar with 0.100M of NAOH requires 33.00cm to reach the
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    2. OSCAR asked by OSCAR
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  7. Vinegar contains ethanoic acid (CH3OOH).titration of 3.00g of vinegar with 0.12M NAOH Solution requires 23.0cm3 to reach the
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    2. Ekekhide asked by Ekekhide
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  8. The concentration of vinegar was obtained by titration. 20 ml of vinegar required 43.2 ml of 0.350 M sodium hydroxide. Find the
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    2. luther asked by luther
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  9. Vinegar contain ethanoic acid.titration of 3.00g of vinegar with 0.12mol NaOH solution requires 23.0cm to reach the equivalence
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    2. Rufinat asked by Rufinat
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  10. 3.30 mL of vinegar needs 43.0 mL of 0.150 M NaOH to reach the equivalence point in a titration, how many grams of acetic acid
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    2. karen asked by karen
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