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Suppose 500 ml of a .0035 M solution of lead

Suppose 500 ml of a .0035 M solution of lead nitrate is reacted with sulfuric acid. What mass of lead sulfate should
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the concentration of OH ions in a household ammonia cleaning solution is0.0035M. Calculate the concentration of H ions.would it
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Suppose 0.490g of lead(II) acetate is dissolved in 50 mL of a 57.0 m M aqueous solution of ammonium sulfate. Calculate the final
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suppose 100 g of lead nitrate salt is added to enough water to make 1 L of solution, what is the concentration of the lead ion
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2. asked by Anonymous
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suppose 100 g of lead nitrate salt is added to enough water to make 1 L of solution, what is the concentration of the lead ion
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2. asked by Anonymous
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i didA=pi(1/48)^2=.0014 2.5 ft/sec * .0014ft .0035 ft^3 450 galmin/1 ft^3/sec * .0035 ft^3/sec*15 min = 23.625 gpm
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2. asked by Matt to drwls
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Suppose I take a 1.0 L saturated, room temp solution of lead(2)bromide and dissolve 1.3g of potassium bromide in the solution.
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2. asked by Olivia
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What is the pH of a .0035 M Ba(OH)2 solution.I did -log(.0070) to find pOH So 14-2.15=11.85 pH? Just want to double check.
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2. asked by Sarah
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Suppose we have a solution of lead nitrate, Pb(NO3). A solution of NaCl(aq) is added slowly until no further precipitation
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2. asked by Katherine
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If 32.0 mL lead(II) nitrate solution reacts completely with excess sodium iodide solution to yield 0.545 g precipitate, what is
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2. asked by Hel P.
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