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Solve each trig identity. a)

Use the identity sin^2x+cos^2x=1 and the fact that sin^2x and cos^2x are mirror images in [0,pi/2], evaluate the integral from
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2. asked by Andre
3. 600 views
Use the identity sin^2x+cos^2x=1 and the fact that sin^2x and cos^2x are mirror images in [0,pi/2], evaluate the integral from
1. 1 answer
2. asked by Rostrastics
3. 660 views
could someone please refresh my memory of the basic trig functions?ex) cos^2 + sin^2 = 1? That is a trig identity.
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2. asked by raychael
3. 628 views
how do you solve this trig identity? i don't get it at all!cos(a+b)cos(a-b)=cos^2a-cos^2b-1
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2. asked by sakura
3. 563 views
Solve each trig identity:a) cos^4(x) - sin^4(x) = cos^2(x) b) cos4(x) = cos^2(x) - sin^2(x)
1. 1 answer
2. asked by jennie
3. 282 views
How do you solve this trig identity problem without factoring?I just used @ to represent theta: sin^4@ + 2sin^2@cos^2@ + cos^4@
1. 2 answers
2. asked by Sammy
3. 581 views
How do you solve this trig identity?Using @ as theta: Sin@-1/sin@+1 = -cos@/(sin@+1)^2 I've tried it multiple times but I can't
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2. asked by Sammy
3. 525 views
Use a trig identity to combine two functions into one so you can solve for x. (The solution should be valid for any value of t).
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2. asked by Lisa
3. 671 views
Solve each trig identity.a) sec2(x) = [sec^2(x)]/[2 - sec^2(x)] b) sec2(x) = [1 + tan^2(x)]/[1 - tan^2(x)] c) [cot(x) -
1. 1 answer
2. asked by jennie
3. 392 views
Hello, I need help with solving these trig identities. All help is appreciated!1. Establish the Identity: (cos(2x)/1+sin(2x)) =
1. 2 answers
2. asked by Kam
3. 609 views