Asked by Lisa
Use a trig identity to combine two functions into one so you can solve for x. (The solution should be valid for any value of t).
3cos(t) + 3*sqrt(3)*sin(t)=6cos(t-x)
I know that 6 cos(t-x) can be 6(cos(t)cosx(x)+sin(t)sin(x))
I don't know where to go from there though.
3cos(t) + 3*sqrt(3)*sin(t)=6cos(t-x)
I know that 6 cos(t-x) can be 6(cos(t)cosx(x)+sin(t)sin(x))
I don't know where to go from there though.
Answers
Answered by
Steve
what you have now is
3cost + 3√3 sint = 6cosx cost + 6sinx sint
for them to be identical, the coefficients must match:
3 = 6cosx
3√3 = 6sinx
looks like x = π/3
3cost + 3√3 sint = 6cosx cost + 6sinx sint
for them to be identical, the coefficients must match:
3 = 6cosx
3√3 = 6sinx
looks like x = π/3
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.