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Solve: (2+x)(-sinx)
Prove the following:
[1+sinx]/[1+cscx]=tanx/secx =[1+sinx]/[1+1/sinx] =[1+sinx]/[(sinx+1)/sinx] =[1+sinx]*[sinx/(sinx+1)]
3 answers
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Anonymous
950 views
solve each equation for 0=/<x=/<2pi
sin^2x + 5sinx + 6 = 0? how do i factor this and solve? 2sin^2 + sinx = 0 (2sinx - 3)(sinx
7 answers
asked by
sh
957 views
the problem is
2cos^2x + sinx-1=0 the directions are to "use an identity to solve each equation on the interval [0,2pi). This is
3 answers
asked by
alex
874 views
Mathematics - Trigonometric Identities - Reiny, Friday, November 9, 2007 at 10:30pm
(sinx - 1 -cos^2x) (sinx + 1 - cos^2x) should
3 answers
asked by
Anonymous
788 views
Solving Trigonometic Equations
solve for x and give the answers as a equations : ( by radian) 1)cos(sinx)=1 <<<and thanks >>> We
0 answers
asked by
abdo
686 views
Simplify sin x cos^2x-sinx
Here's my book's explanation which I don't totally follow sin x cos^2x-sinx=sinx(cos^2x-1)
1 answer
asked by
Tara
1,061 views
solve to four decimals places
5.0118 sinx - 3.1105=0 :for all real x values I will be happy to critique your work. Solve for
2 answers
asked by
Kate
543 views
Hello! Can someone please check and see if I did this right? Thanks! :)
Directions: Find the exact solutions of the equation in
1 answer
asked by
Maggie
857 views
solve to four decimal places
1.3224sinx + 0.4732=0 :for all real x values solve for sinx, then arcsinx. solve for sinx, then
0 answers
asked by
Kate
576 views
Could someone check my reasoning? thanx
Find the derivative of the function. sin(sin[sinx]) I need to use the chain rule to
1 answer
asked by
XCS
767 views