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PCl5 dissociates according to the

PCl5 dissociates according to the reaction: PCl5(g) ↔ PCl3(g) + Cl2(g). One mole of PCl5 was placed in one liter of solution.
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2. asked by Sam
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In the gaseous phase PCl5 dissociates according to the following equilibrium: PCl5⇌PCl3+Cl2 and Kc=0.8 at 613K .Determine the
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2. asked by Anonymous
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for each mole of PCL5 which dissociates, how many moles of CL2 are produced
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2. asked by bec
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A 1.500 mol sample of PCL5 dissociates at 160C and 1.00 atm to give 0.203 mol of PCL3 at equilibrium. What is the composition of
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2. asked by Darlice
3. 400 views
Phosphorus pentachloride dissociates on heating:PCl5(g) ⇄ PCl3(g) + Cl2(g) 𝝙H = 1901 kJ/mol (a) If Kc equals 3.26 
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2. asked by Patrick
3. 675 views
For the following reaction at 600. K, the equilibrium constant, Kp, is 11.5.PCl5(g) = PCl3(g) + Cl2(g) Suppose that 2.510 g of
1. 2 answers
2. asked by Writeacher
3. 3,055 views
For the following reaction at 600. K, the equilibrium constant, Kp is 11.5.PCl5(g) PCl3(g) + Cl2(g) Suppose that 3.314 g of PCl5
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2. asked by Anonymous
3. 1,224 views
At a certain temperature, .5 mol of PCl5 was placed in a .25 L vessel and permitted to react as shownPCl5 (g) --> PCl3 (g)+ Cl2
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2. asked by Alex
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At a certain temperature, 2.00 moles of phosphorus(V) chloride, PCl5, was placed in a 1.0 L vessel and permitted to react as
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2. asked by chem
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a sample of pcl5 weighing 2.69 placed in 1.0 l flask and completely vaporized at a tem of 250 c the pressur at this tempreture
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2. asked by biran
3. 1,124 views