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Na2SO4(aq)+CaI2(aq)→CaSO4(s)+2NaI(aq) as net ionic
Na2SO4(aq)+CaI2(aq)→CaSO4(s)+2NaI(aq) as net ionic
1 answer
asked by
Anonymous
3,228 views
I have tried virtually everything, i can't fogure out this problem. I have 2K^+ + SO4^2- + Ca^2+ + 2I^- --> CaSO4(s) + 2K^+ +
1 answer
asked by
Amy
2,592 views
Na₂SO₄(aq) + CaCl₂(aq) -> CaSO₄ (s) + 2NaCl(aq)
Now that we have a balanced chemical equation, let's write the ionic
1 answer
asked by
Tristan
1,867 views
do not understand this problem
The Ksp of CaSO4 is 4.93× 10–5. Calculate the solubility (in g/L) of CaSO4(s) in 0.500 M
2 answers
asked by
Mohsain
7,025 views
If 100.0 mL of 0.0025 M Na2SO4
(aq)is saturated with CaSO4 how many grams of CaSO4 would be present in the solution? [Hint: Does
0 answers
asked by
sarah
936 views
Below are the formulas of some hydrates. what is the mole ratio of salt to water?
Hydrate Na2SO4.10H2O Co(NO3)2.6H2O
4 answers
asked by
Rose
3,817 views
The Ksp of CaSO4 is 4.93× 10–5. Calculate the solubility (in g/L) of CaSO4(s) in 0.300 M Na2SO4(aq) at 25 °C
1 answer
asked by
Katherine
6,615 views
Balance the following:
Ca(OH) + H2SO4 -----> CaSO4 + H2O Na2S2O3 + I2 -----> 2NaI + Na2S4O6 ZnCl + Na2S -----> ZnS + NaCl SnCl4 +
1 answer
asked by
Akira
1,758 views
What is the approximate ratio of the solubility of CaSO4 (Ksp = 2.4 x 10−5) in pure water to the solubility of CaSO4 in 0.10 M
3 answers
asked by
bill
1,850 views
you made up a standard solution of calcium sulfate (CaSO4). the temperature is 25C. you then add 5.00*10^-3 odium sulfate
2 answers
asked by
Maria
969 views