N2(g)+3F2 yields 2Nf3(g) Delta H(degree)298=-264KJ

  1. N2(g)+3F2 yields 2Nf3(g)Delta H(degree)298=-264KJ mol-1;Delta S(degree)298=-278J K-1 mol-1 The following questions relate to the
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    2. Jenna asked by Jenna
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  2. consider the following changes at constant temperature & pressureH2O(s) --yields-- H20(l); Delta H1 H2O(l) --yields-- H2O(g);
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    2. marcus asked by marcus
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  3. Consider the following data:* NH3(g) yields 1/2 N2(g) + 3/2 H2(g) delta H = 46kJ * 2 H2(g) + O2(g) yields 2 H2o(g) delta H =
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    2. Shellby asked by Shellby
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  4. 2NF3(g) yields N2(g) + 3F2(g)When 2.06 mol of NF3 is placed in a 2.00L container and allowed to come to equilibrium at 800K, the
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    2. Robby asked by Robby
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  5. I really dk how to do them,i have spend hours doing itCan somebody please solve and if possible show the steps thx,just 3
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    2. idkhowtodomath asked by idkhowtodomath
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  6. consider the following reaction at 298K4Al(s)+3O2(g) yields 2Al2O3(s) delta H= -3351.4 Kj find delta S sys find delta S surr
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    2. Jessica asked by Jessica
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  7. consider the following reaction at 298K4Al(s)+3O2(g) yields 2Al2O3(s) delta H= -3351.4 Kj find delta S sys find delta S surr
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    2. Jake asked by Jake
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  8. Hey guys! I'm really lost on this equation. Any help?H2(g) yIelds 2H(g) Delta H = 436 kJ/mol F2(g) yields 2F(g) DeltaH = 158
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    2. Allie asked by Allie
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  9. Given that E^o = 0.52 V for the reduction of Cu+(aq) + e - (yields) Cu(s)Calculate E^o, (delta)G^o and K for the following
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    2. Julie asked by Julie
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  10. Does my work here look right?3. One mole of an ideal gas expands adiabatically into a vacuum. Calculate q, delta-e, w, and
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    2. Jess asked by Jess
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