Asked by marcus
consider the following changes at constant temperature & pressure
H2O(s) --yields-- H20(l); Delta H1
H2O(l) --yields-- H2O(g); Delta H2
H2O(g) --yields-- H2O(s); Delta H3
Using Hess's law, the sum of the deltas is
a. equal to 0
b. sometimes greater than zero, sometimes less than zero
c. less than 0
d. cannot be determined without the numerical values of delta H
e. greater than 0
I picked e because delta 1 looks to be an endothermic reaction, delta 2 also endothermic, and delta 3 is exothermic reaction. But the answer is equal to 0. Why?
H2O(s) --yields-- H20(l); Delta H1
H2O(l) --yields-- H2O(g); Delta H2
H2O(g) --yields-- H2O(s); Delta H3
Using Hess's law, the sum of the deltas is
a. equal to 0
b. sometimes greater than zero, sometimes less than zero
c. less than 0
d. cannot be determined without the numerical values of delta H
e. greater than 0
I picked e because delta 1 looks to be an endothermic reaction, delta 2 also endothermic, and delta 3 is exothermic reaction. But the answer is equal to 0. Why?
Answers
Answered by
DrBob222
dHsub = dHfusion + dHvaporization
So you add dHfusion to dHvap and you end up with dHsub which means that if you complete the cycle you end you with zero.
So you add dHfusion to dHvap and you end up with dHsub which means that if you complete the cycle you end you with zero.
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