Ask a New Question
Search
Moles of S203^2- = (molarity)(volume):
Please refer to the previous post Chemistry Help Please.
Moles of S203^2- = (molarity)(volume): =(0.032400 mol/L)(0.053 litres
6 answers
asked by
Sara
693 views
Moles of S203^2- = (molarity)(volume):
=(0.032400 mol/L)(0.053 litres S203^2-) = 0.03240 moles S203^2- Moles if I2 based on
2 answers
asked by
Sara
882 views
What is the molarity of a solution 12.5 naoh dissolved in total volume of 625ml?
NaOH = 12.5/molar mass of NaOH = 12.5/39.99 =
5 answers
asked by
sarah
564 views
My problem is calculate the molarity of HCl and NaOH.
(molarity of acid)x(volume of acid)=(molarity of base)+(volume of added
2 answers
asked by
Brad
647 views
My problem is calculate the molarity of HCl and NaOH
(molarity of acid)x(volume of acid)=(molarity of base)+(volume of added
0 answers
asked by
Chemistry
657 views
how are moles and molarity related to volume? is it molx molarity or mol/molarity to get volume?
1 answer
asked by
jackson
598 views
Hi, I did the acid-base titration lab with HCl and 0.5M NaOH.
I need to calculate the moles of NaOH from molarity of NaOH and the
2 answers
asked by
Kim
2,917 views
more volume of NaOH means more moles of NaOH (volume * molarity = mole ; molarity=constant) , more moles of NaOH means more
1 answer
asked by
fred
1,066 views
What is the molarity (M) of an HCl solution, 150 ml of which when treated with excess magnesium liberates 3.5 l of H2 gas
0 answers
asked by
Johnie HELPPPPP
562 views
2 questions, I'm Having trouble figuring out how to calculate the moles of a solute in a solution based on the molarity and the
1 answer
asked by
Courtney
636 views