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Moles of S203^2- = (molarity)(volume):

  1. Please refer to the previous post Chemistry Help Please.Moles of S203^2- = (molarity)(volume): =(0.032400 mol/L)(0.053 litres
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    2. Sara asked by Sara
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  2. Moles of S203^2- = (molarity)(volume):=(0.032400 mol/L)(0.053 litres S203^2-) = 0.03240 moles S203^2- Moles if I2 based on
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    2. Sara asked by Sara
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  3. What is the molarity of a solution 12.5 naoh dissolved in total volume of 625ml?NaOH = 12.5/molar mass of NaOH = 12.5/39.99 =
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    2. sarah asked by sarah
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  4. My problem is calculate the molarity of HCl and NaOH.(molarity of acid)x(volume of acid)=(molarity of base)+(volume of added
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    2. Brad asked by Brad
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  5. My problem is calculate the molarity of HCl and NaOH(molarity of acid)x(volume of acid)=(molarity of base)+(volume of added
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    2. Chemistry asked by Chemistry
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  6. how are moles and molarity related to volume? is it molx molarity or mol/molarity to get volume?
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    2. jackson asked by jackson
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  7. Hi, I did the acid-base titration lab with HCl and 0.5M NaOH.I need to calculate the moles of NaOH from molarity of NaOH and the
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    2. Kim asked by Kim
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  8. more volume of NaOH means more moles of NaOH (volume * molarity = mole ; molarity=constant) , more moles of NaOH means more
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    2. fred asked by fred
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  9. What is the molarity (M) of an HCl solution, 150 ml of which when treated with excess magnesium liberates 3.5 l of H2 gas
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    2. Johnie HELPPPPP asked by Johnie HELPPPPP
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  10. 2 questions, I'm Having trouble figuring out how to calculate the moles of a solute in a solution based on the molarity and the
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    2. Courtney asked by Courtney
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