Mg3N2(s) + 6H20 = Mg(OH)2(s)

  1. Mg3N2(s) + 6H20 = Mg(OH)2(s) + 2NH3(g)When 2 moles of H20 react How many grams of NH3 are produced ?
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    2. Mohamed asked by Mohamed
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  2. Mg3N2 + 6H20 = 3Mg(OH) + 2NH3What mass of magnesium nitride would you need to react with excess water to produce 25g of ammonia?
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    2. Stephanie asked by Stephanie
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  3. 2. What is the percent yield of Mg3N2 if 73.9 g of Mg reacts with 31.6 g of N2 to produce 79 g of Mg3N2 according to the
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    2. brittany asked by brittany
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  4. 1 mol Cu(NO3)2*6H20 X 295.69g Cu(NO3)2*6H20/ mol Cu(N03)2*6H20=___________ gCu(NO3)2*6H20what does in the blank?
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    2. peter asked by peter
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  5. For the reaction3 Mg + N2 → Mg3N2 , what is the maximum amount of Mg3N2 which could be formed from 6.66 mol of Mg and 9.34 mol
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    2. Dani asked by Dani
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  6. which equation best models, cellular respiration 6H20 + 6CO, + Energy - CgH1206 + 602 O CgH1206 + 602 - 6H20 + 6C02 + Energy O
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    2. 凸(¬‿¬) asked by 凸(¬‿¬)
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  7. the element nitrogen and magnesium react to give magnesium nitride according to the balanced equationN2 + 3Mg = Mg3N2 suppose
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    2. burrprett asked by burrprett
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  8. When 2.50 mol of Mg3N2 are allowed to react according to the following equation, how many moles of H2O also react?Mg3N2 + 6H2O
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    2. Soojung asked by Soojung
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  9. 0.197g of magnesium is burned in air2Mg + O2 ---> 2MgO However, some of the magnesium reacts with nitrogen in the air to form
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    2. Chansa asked by Chansa
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  10. Which of the following is the chemical equation for cellular respiration? (1 point)• C6H120 + 60г → 6C02 + 6H20 + Energy
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