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Mg3N2(s) + 6H20 = Mg(OH)2(s)
Mg3N2(s) + 6H20 = Mg(OH)2(s) + 2NH3(g)
When 2 moles of H20 react How many grams of NH3 are produced ?
1 answer
asked by
Mohamed
1,350 views
Mg3N2 + 6H20 = 3Mg(OH) + 2NH3
What mass of magnesium nitride would you need to react with excess water to produce 25g of ammonia?
1 answer
asked by
Stephanie
1,446 views
2. What is the percent yield of Mg3N2 if 73.9 g of Mg reacts with 31.6 g of N2 to produce 79 g of Mg3N2 according to the
1 answer
asked by
brittany
883 views
1 mol Cu(NO3)2*6H20 X 295.69g Cu(NO3)2*6H20/ mol Cu(N03)2*6H20=___________ gCu(NO3)2*6H20
what does in the blank?
3 answers
asked by
peter
431 views
For the reaction
3 Mg + N2 → Mg3N2 , what is the maximum amount of Mg3N2 which could be formed from 6.66 mol of Mg and 9.34 mol
2 answers
asked by
Dani
1,318 views
which equation best models, cellular respiration 6H20 + 6CO, + Energy - CgH1206 + 602 O CgH1206 + 602 - 6H20 + 6C02 + Energy O
1 answer
asked by
凸(¬‿¬)
80 views
the element nitrogen and magnesium react to give magnesium nitride according to the balanced equation
N2 + 3Mg = Mg3N2 suppose
1 answer
asked by
burrprett
577 views
When 2.50 mol of Mg3N2 are allowed to react according to the following equation, how many moles of H2O also react?
Mg3N2 + 6H2O
4 answers
asked by
Soojung
6,523 views
0.197g of magnesium is burned in air
2Mg + O2 ---> 2MgO However, some of the magnesium reacts with nitrogen in the air to form
3 answers
asked by
Chansa
886 views
Which of the following is the chemical equation for cellular respiration? (1 point)
• C6H120 + 60г → 6C02 + 6H20 + Energy
1 answer
18 views