Asked by Stephanie
Mg3N2 + 6H20 = 3Mg(OH) + 2NH3
What mass of magnesium nitride would you need to react with excess water to produce 25g of ammonia?
What mass of magnesium nitride would you need to react with excess water to produce 25g of ammonia?
Answers
Answered by
DrBob222
I have corrected your equation.
Mg3N2 + 6H20 = 3Mg(OH)2 + 2NH3
How many mols NH3 are in 25 g? That's mols = grams/molar mass = 25/17 = estimated 1.5 but you need to use a more accurate number.
Convert mols NH3 to mols Mg3N2 using the coefficients in the balance equation.
1.5 mols NH3 x (1 mol Mg3N2/2 mol NH3) = estimated 0.75 Mg3N2. Now convert that to grams. g = mols Mg3N2 x molar mass Mg3N2
Post your work if you get stuck.
Mg3N2 + 6H20 = 3Mg(OH)2 + 2NH3
How many mols NH3 are in 25 g? That's mols = grams/molar mass = 25/17 = estimated 1.5 but you need to use a more accurate number.
Convert mols NH3 to mols Mg3N2 using the coefficients in the balance equation.
1.5 mols NH3 x (1 mol Mg3N2/2 mol NH3) = estimated 0.75 Mg3N2. Now convert that to grams. g = mols Mg3N2 x molar mass Mg3N2
Post your work if you get stuck.
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