It's in sigma notation, so

  1. I just need help with this.Write the series in sigma notation. 1/4 + 1/2+ 3/4 + 1 + 5/4 + 3/2 5 A.) 1/4 sigma N n=1 6 B.) 1/4
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 852 views
  2. I just need help with this.Write the series in sigma notation. 1/4 + 1/2+ 3/4 + 1 + 5/4 + 3/2 5 A.) 1/4 sigma N n=1 6 B.) 1/4
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 475 views
  3. If I wanted to rightSIGMA F = ma in the proper notation what would I put above and below SIGMA Would I put a lower case "n"
    1. answers icon 1 answer
    2. Kate asked by Kate
    3. views icon 540 views
  4. If I wanted to rightSIGMA F = ma in the proper notation what would I put above and below SIGMA Would I put a lower case "n"
    1. answers icon 2 answers
    2. Kate asked by Kate
    3. views icon 823 views
  5. Please help-I need to write 4+6+8+10 in sigma notationwould it be sigma sign in middle (3) on top of sign, n=0 on bottom of
    1. answers icon 1 answer
    2. Julia asked by Julia
    3. views icon 527 views
  6. Given that; Sigma*x = 52; n = 8; Sigma*y = 225; Sigma*xy = 1335; Sigma * x ^ 2 = 380; Sigma * y ^ 2 = 7007 and Calculated the
    1. answers icon 1 answer
    2. views icon 77 views
  7. hii startted the problem below by writing a sigma notation of sigma[(2^(n+1))/((n+1)!)] QUESTION: how do i find the sum of
    1. answers icon 1 answer
    2. kiksy asked by kiksy
    3. views icon 481 views
  8. hii startted the problem below by writing a sigma notation of sigma[(2^(n+1))/((n+1)!)] QUESTION: how do i find the sum of
    1. answers icon 0 answers
    2. kiksy asked by kiksy
    3. views icon 441 views
  9. Express the sum using summation notation:1 - 1/2 + 1/3 - 1/4 + 1/5 - ... (to 3n terms) If I'm doing this right so far, with k=1
    1. answers icon 0 answers
    2. Please Help asked by Please Help
    3. views icon 1,041 views
  10. Express the sum using summation notation:1 - 1/2 + 1/3 - 1/4 + 1/5 - ... (to 3n terms) If I'm doing this right so far, with k=1
    1. answers icon 0 answers
    2. Anonymous asked by Anonymous
    3. views icon 468 views