In the equation: 2Al+6HCl-->2AlCl3+3H2 Why

  1. Al2O3+6HCL=2ALCL3+3H2O its equation is ?
    1. answers icon 1 answer
    2. samrat asked by samrat
    3. views icon 1,082 views
  2. assume that 13.5g of AL react with excess HCl according to the following balanced equation, at STP: 2Al(s) + 6HCl(aq) --->
    1. answers icon 1 answer
    2. Joe asked by Joe
    3. views icon 887 views
  3. 2Al(s)+6HCl(aq)➡️2AlCl3(aq)+3H2(g)What are the oxidation numbers for elements on both sides of the equation? which element
    1. answers icon 1 answer
    2. Carmen asked by Carmen
    3. views icon 147 views
  4. how many moles of HCl will be produced when 30g of H2O are reacted according to the chemical equation 2AlCl3 + 3H2O -> Al2O3 +
    1. answers icon 1 answer
    2. bekah asked by bekah
    3. views icon 1,448 views
  5. Identify the equation(s) that is/are not balanced.Check all that apply. C2H2(g)+ 402(g)-+2C02(g)+2H20(g) SiCl4(1)+2H2O(1) +
    1. answers icon 1 answer
    2. views icon 56 views
  6. Based on the balanced equation2Al + 6HCl → 2AlCl3 + 3H2 calculate the number of excess reagent units remaining when 140 Al
    1. answers icon 2 answers
    2. eng asked by eng
    3. views icon 2,061 views
  7. Find the mass of AlCl3 that is produced when 10.0 grams of Al2O3 react with 25.0 g of HCl according to the following equation.Al
    1. answers icon 1 answer
    2. ZEE asked by ZEE
    3. views icon 3,959 views
  8. Please help me with this-- I don't understand it.Calculate the change of enthalpy for the reaction 2Al (s) + 3Cl2 (g) --> 2AlCl3
    1. answers icon 1 answer
    2. graf asked by graf
    3. views icon 849 views
  9. how many grams of H2 (g) are produced by the reaction of 1.35 g Al with 75.0 mL of 3.44 M HClHere is the way to do most of these
    1. answers icon 0 answers
    2. brian asked by brian
    3. views icon 625 views
  10. Commerical hydrochloric acid is 37% by mass HCl and has a solution density of 1.18g/mL. What minimum volume of hydrocloric acid
    1. answers icon 1 answer
    2. Anonymous asked by Anonymous
    3. views icon 643 views