Asked by Carmen

2Al(s)+6HCl(aq)➡️2AlCl3(aq)+3H2(g)
What are the oxidation numbers for elements on both sides of the equation? which element is being oxidized and which is being reduced?

Answers

Answered by DrBob222
Al is zero on the left and 3+ on the right. Loss of 3 electrons/atom
H is 1+ on the left and 0 on the right. Gain of 1 electron/atom
Cl is 1- on the left and 1- on the right. No change.
Oxidation is the loss of electrons. Reduction is the gain of electrons.
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