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If vinegar sample #1 requires

A 3.455 g sample of vinegar is titrated. It requires 16.83 mL of 0.2145 M NaOH to get to the phenolphthalein end point.
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2. asked by ashlee
3. 633 views
calculate the molarity of acetic acid in a vinegar sample,knowing that 5.00ml of vinegar requires 43.50ml of 0.105 M NaOH to
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2. asked by denis
3. 3,969 views
calculate the molarity of acetic acid in a vinegar sample,knowing that 5.00ml of vinegar requires 43.50ml of 0.105 M NaOH to
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2. asked by denis
3. 963 views
A 50ml sample of vinegar is titrated with 0.774M NaOH(aq). If the titration requires 41.6ml of NaOH(aq), what is the
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2. asked by Steve
3. 950 views
12.5g mass of the vinegar sample and the density of vinegar is 1.05g/mL determine the volume of the vinegar sample in liters?
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2. asked by Anonymous
3. 886 views
Vinegar contains acetic acid CH3COOH. Titration of 5.000g vinegar with 0.100M NaOH requires 33.0cm cube to reach the equivalence
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2. asked by Anonymous
3. 381 views
1. Harry titrates vinegar with 0.952 M NaOH. The sample was 25.75 mL of vinegar, and it took 19.85 ml of 0.952 M NaOH to reach
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2. asked by tori
3. 557 views
A vinegar contains acetic acid, CH3COOH. Titration of 5.000g of vinegar with 0.100, NaOH requires 33.0 ml to reach equivalent
1. 4 answers
2. asked by Anonymous
3. 4,580 views
a vinegar contains acetic acid,CH3COOH.Titration of 5.00g of vinegar with 0.100M of NAOH requires 33.00cm to reach the
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2. asked by OSCAR
3. 1,343 views
Vinegar contains ethanoic acid (CH3OOH).titration of 3.00g of vinegar with 0.12M NAOH Solution requires 23.0cm3 to reach the
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2. asked by Ekekhide
3. 1,361 views