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If 4.50 g of (NH4)2SO4

  1. 4.0 gram of ferrous ammonium sulphate, FeSO4*(NH4)2SO4 * 6H2O, is used. Since the oxalate is in excess , Calculate the
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    2. Pat asked by Pat
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  2. 4.0 gram of ferrous ammonium sulphate, FeSO4*(NH4)2SO4 * 6H2O, is used. Since the oxalate is in excess , Calculate the
    1. answers icon 1 answer
    2. Kesha asked by Kesha
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  3. HOW MANY MOLES OF NH3 WOULD BE FORMED FROM 50 GRAMS OF (NH4)2SO4 IN THE FOLLOWING EQUATION?(NH4)2SO4 + 2 NaOH=2NH3 + 2 H2O +
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    2. ANGELA asked by ANGELA
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  4. how many kilograms of NH3 are needed to produce 2.90x10^5kg of (NH4)2SO4?the balanced equation is: 2 NH3 + H2SO4 --> (NH4)2SO4
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    2. Kelly asked by Kelly
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  5. how many kilograms of NH3 are needed to produce 2.90x10^5kg of (NH4)2SO4?the balanced equation is: 2 NH3 + H2SO4 --> (NH4)2SO4
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    2. Kelly asked by Kelly
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  6. How many grams of ammonium sulfate, (NH4)2SO4, would you need to prepare 100.00 mL of a 5.00 x 10^-2 M (NH4)2SO4 solution?
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    2. Anonymous asked by Anonymous
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  7. What is the formula of magnesium sulfate and ammonia?My work:MgSO4 + 2NH4OH --> (NH4)2SO4 + Mg(OH)2 Correct/Balance the equation
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    2. DFD asked by DFD
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  8. A saturated solution of ammonium sulfate, (NH4)2SO4, in water at 30 0C contains 78.0 g (NH4)2SO4 per 100.0 g H2O. What is the
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    2. robert asked by robert
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  9. QUESTION 6 [20 marks]The fertiliser ammonium sulphate ((NH4 )2SO4 ) is produced from the reaction of sulphuric acid (H2SO4 ) and
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  10. How many moles of ammonium ions and how many moles of sulfate ions are contaiuned in a 0.400 mile sample of (NH4)2SO4?Referring
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    2. Chelsea asked by Chelsea
    3. views icon 832 views