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I have 3NaBH4 + 4BF3.Et2O

  1. I have 3NaBH4 + 4BF3.Et2O to form 2B2H6 th number of moles of NaBH4 is 0.0368mol and the number of moles of BF3.Et2O is
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    2. help asked by help
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  2. How many moles of NaBH4 are needed to generate one mole of B2H6 if the reaction gives an 80% yield?3NaBH4 +4BF3 �¨ 3NaBF4 +
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    2. Dan asked by Dan
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  3. 4BF3+3H2O=H3BO3+3HBF4if the reaction vessel contains 0.496 mol BF3 and 5.63g of H2O, which compound is the limiting reactant?
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    2. dana asked by dana
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